Form New Equation
(1) \((x - \alpha)(x - \beta)(x - \gamma) = 0\)
If \(\alpha, \beta\) and \(\gamma\) are known.
(2) \(x^3 - (\alpha + \beta + \gamma) \:.\: x^2 + (\alpha \:.\: \beta + \alpha \:.\: \gamma + \beta \:.\: \gamma) \:.\: x - (\alpha \:.\: \beta \:.\: \gamma) = 0\)
If relations of \(\alpha, \beta\) and \(\gamma\) are known.
Example
Find the equation which roots are −4, 3 and 5.
First method
\begin{equation*} \begin{split} & (x - \alpha)(x - \beta)(x - \gamma) = 0 \\\\ & (x + 4)(x - 3)(x - 5) = 0 \\\\ & (x^2 + x - 12)(x - 5) = 0 \\\\ & x^3 - 4x^2 - 17x + 60 = 0 \end{split} \end{equation*}
Second method
\(\alpha + \beta + \gamma\)
\(-4 + 3 + 5\)
\(4\)
\(\alpha \:.\: \beta + \alpha \:.\: \gamma + \beta \:.\: \gamma\)
\(-4 \:.\: 3 + -4 \:.\: 5 + 3 \:.\: 5\)
\(- 17\)
\(\alpha \:.\: \beta \:.\: \gamma\)
\(-4 \:.\: 3 \:.\: 5\)
\(- 60\)
Equation
\begin{equation*} \begin{split} & x^3 - (\alpha + \beta + \gamma)x^2 + (\alpha \:.\: \beta + \alpha \:.\: \gamma + \beta \:.\: \gamma)x - (\alpha \:.\: \beta \:.\: \gamma) = 0 \\\\ & \bbox[5px, border: 2px solid magenta] {x^3 - 4x^2 - 17x + 60 = 0} \end{split} \end{equation*}
Exercise