Dalam ruang 4 liter dicampurkan alumunium dan asam sulfat masing-masing 1 mol menurut reaksi:
Setelah kesetimbangan tercapai, terdapat 0,6 mol \(\ce{Al}\). Tentukan harga tetapan kesetimbangan Kc.
Reaksi kesetimbangan
\begin{equation*}
\begin{array}
& & \ce{2 Al (s)} & + & \ce{3 H2SO4 (aq)} & \ce{<=>} & \ce { Al2(SO4)3 (aq)} & + & \ce{ 3 H2(g)} \\
\text{Mula-mula} & 1 & & 1 && - & & - \\
\text{Reaksi} & 0,4 & & 0,6 && 0,2 & & 0,6 \\
\text{Akhir} & 0,6 & & 0,4 && 0,2 & & 0,6
\end{array}
\end{equation*}
Tetapan kesetimbangan Kc
\begin{equation*}
\begin{split}
Kc & = \frac {[\ce{Al2(SO4)3}] \:.\: [\ce{H2}]^2}{[\ce{H2SO4}]^3} \\\\
Kc & = \frac {[\frac {0,2}{4}] \:.\: [\frac {0,6}{4}]^2}{[\frac {0,4}{4}]^3} \\\\
Kc & = \left[\frac {0,2}{4}\right] \:.\: \left[\frac {0,6}{4}\right]^2 \:.\: \left[\frac {4}{0,4}\right]^3 \\\\
Kc & = \frac {0,2 \:.\: [0,6]^2}{[0,4]^3} \\\\
Kc & = \frac {9}{8}
\end{split}
\end{equation*}