Example

A person walks from A to D through B and C as diagram below,

Determine:

A. Distance and displacement of the person

Distance travelled by the person is $5+10+5=20\text{ m}$

Displacement of the person is $10\text{ m}$

B. Average speed and average velocity of the person

$\text{Average speed}={\displaystyle \frac{\text{distance}}{\text{time}}}={\displaystyle \frac{20}{10}}=2\text{ m/s}$

$\text{Average velocity}={\displaystyle \frac{\text{displacement}}{\text{time}}}={\displaystyle \frac{10}{10}}=1\text{ m/s}$