Persamaan Gas Ideal

A.   Jumlah mol gas H₂S

\begin{equation*}
\begin{split}
P \:.\: V& = n \:.\: R \:.\: T \\\\
2 \:.\: 5& = n\:.\: 0,082 \:.\: (27 + 273) \\\\
n& = \frac{2 \:.\: 5}{0,082 \:.\: (27 + 273)} \\\\
n& = 0,41 \text{ mol } \ce{H2S}
\end{split}
\end{equation*}

B.   Massa senyawa H₂S

\begin{equation*}
\begin{split}
n& = \frac{m}{Mr} \\\\
0,41& = \frac{m}{ (2 \times 1) + 32} \\\\
m& = 0,41 \times 34 \\\\
m & = 13,94 \text{ gram } \ce{H2S}
\end{split}
\end{equation*}

C.   Jumlah partikel H₂S dalam tabung tersebut

\begin{equation*}
\begin{split}
n& = \frac{N}{N_A} \\\\
0,41& = \frac{N}{6,02 \times 10^{23}} \\\\
N& = 0,41 \times 6,02 \times 10^{23} \\\\
N& = 2,468 \times 10^{23} \: \text{molekul } \ce{H2S}
\end{split}
\end{equation*}