Factorise \(32ab + 8ac\) completely.
\begin{equation*}
\begin{split}
&\text{Both 32ab and 8ac can be divided by 8a, therefore the HCF is 8a}\\\\
&32ab + 8ac = 8a(4b + c)\:\:\:\:\:\color {red} \text{take out common factor 8a}
\end{split}
\end{equation*}