Soal 01
Bentuk sederhana dari \((3x )^2 - (3x - 4)^2 = \dotso\)
(A) \(9x^2 - 16x + 16\)
(B) \(6x^2 + 24x + 16\)
(C) \(4(4 - 6x)\)
(D) \(8(3x - 2)\)
(E) \(16\)
Soal 02
Bentuk sederhana dari \(\dfrac {6 - 3x}{x^2 - 5x + 6} = \dotso\)
(A) \(\dfrac {1}{x}\)
(B) \(\dfrac {1}{3x}\)
(C) \(\dfrac {1}{3x + 1}\)
(D) \(\dfrac {3}{x - 3}\)
(E) \(\dfrac {3}{3 - x}\)
Soal 03
Bentuk sederhana dari \(\dfrac {4x^2 - 25}{15 + x - 2x^2} = \dotso\)
(A) \(\dfrac {2x - 5}{3 - x}\)
(B) \(\dfrac {2x - 5}{3x + 1}\)
(C) \(\dfrac {2x + 5}{1 - x}\)
(D) \(\dfrac {2x + 5}{1 - 3x}\)
(E) \(\dfrac {4x + 5}{3 + x}\)
Soal 04
Bentuk sederhana dari \(\dfrac {1}{x^2 - 4} - \dfrac {1}{2x^2 + 4x} = \dotso\)
(A) \(\dfrac {1}{2x(x - 2)}\)
(B) \(\dfrac {1}{2x(x + 2)}\)
(C) \(\dfrac {1}{4x(x + 2)}\)
(D) \(\dfrac {1}{(x + 2)(x - 2)}\)
(E) \(\dfrac {1}{(x + 4)(x - 4)}\)
Soal 05
Bentuk sederhana dari \(\dfrac {1}{x^3 - 8} + \dfrac {1}{x^2 + 2x + 4} = \dotso\)
(A) \(\dfrac {1}{x^3 - 8}\)
(B) \(\dfrac {x + 1}{x^3 - 8}\)
(C) \(\dfrac {x - 1}{x^3 - 8}\)
(D) \(\dfrac {1}{x^2 + 2x + 4}\)
(E) \(\dfrac {x}{(x + 2)(x^2 + 2x + 4)}\)
Soal 06
Bentuk sederhana dari \(\dfrac {x^4 - 81}{x^3 + 27} = \dotso\)
(A) \(\dfrac {x + 3}{x^2 + 9}\)
(B) \(\dfrac {x + 3}{x^2 + 3x + 9}\)
(C) \(\dfrac {(x + 3)(x^2 + 9)}{x^2 + 27}\)
(D) \(\dfrac {(x - 3)(x^2 + 9)}{x^2 + 3x + 9}\)
(E) \(\dfrac {(x - 3)(x^2 + 9)}{x^2 + 3x + 9}\)
Soal 07
Bentuk sederhana dari \(\dfrac {x - y}{\sqrt{x} + \sqrt{y}} = \dotso\)
(A) \(\sqrt{x} + \sqrt{y}\)
(B) \(\sqrt{x} - \sqrt{y}\)
(C) \(\sqrt{xy}\)
(D) \(x + y\)
(E) \(x - y\)
Soal 08
Bentuk lain dari \(1012 \times 988 = \dotso\)
(A) \(10^3 + 12\)
(B) \(10^3 - 12\)
(C) \(10^3 - 144\)
(D) \(10^6 + 144\)
(E) \(10^6 - 144\)
Soal 09
\(\dfrac {(11^2 - 1)(12^2 - 1)(13^2 - 1)(14^2 - 1)}{(11 \times 12)(12 \times 13)(13 \times 14)(14 \times 15)} = \dotso\)
(A) \(\dfrac 34\)
(B) \(\dfrac 35\)
(C) \(\dfrac 45\)
(D) \(\dfrac 56\)
(E) \(\dfrac 57\)
Soal 10
\(\dfrac {2022 \times 2022 \times 2022 + 2023 \times 2023 \times 2023}{2022 \times 2022 + 2023 \times 2023 - 2022 \times 2023} = \dotso\)
(A) \(1\)
(B) \(2044\)
(C) \(2045\)
(D) \(4044\)
(E) \(4045\)