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PEMBAHASAN SOAL

Gas metana (CH₄) berada dalam ruang bertekanan 0,0082 atm dan suhu −73°C.

Berapakah massa jenis gas metana dalam ruang tersebut?

Ar C = 12, H = 1

Pembahasan:

$$\begin{array}{rl}P.V& =n.R.T\\ \\ P.V& =\frac{m}{Mr}.R.T\\ \\ P.V.Mr& =m.R.T\\ \\ P.Mr& =\frac{m}{V}.R.T\dots \rho =\frac{m}{V}\\ \\ P.Mr& =\rho .R.T\\ \\ 0,0082.{10}^5.(12+4.1)& =\rho .0,082.(-73+273)\\ \\ 0,0082.{10}^5.16& =\rho .0,082.200\\ \\ \rho & =\frac{0,0082.{10}^5.16}{0,082.200}\\ \\ \rho & =\frac{0,1.{10}^5.8}{100}\\ \\ \rho & =800\text{ gr/liter}\\ \\ \rho & =800{\text{ kg/m}}^3\end{array}$$