QUESTION 01 \(\displaystyle \int (x^2-4x+2) \: dx\) \(x^3 - 2x^2 + 2x\) \(x^3 - 2x^2 + 2x + c\)...
QUESTION 03 \(\displaystyle \int \left(\dfrac{2}{x^4}+\dfrac{3}{x}+\dfrac{5}{\sqrt{x}} \right) \: dx\) \(-\dfrac{2}{3x^3}+3\ln|x|+10\sqrt{x}+c\) \(-\dfrac{2}{3x^3}+4 \ln|x|+20\sqrt{x}+c\) \(-\dfrac{5}{3x^3}+4\ln|x|+20\sqrt{x}+c\) \(-\dfrac{2}{3x^3}+2\ln|x|+5\sqrt{x}+c\) 🔍 Solution \begin{equation*} \begin{split} & \int...
QUESTION 03 \(\displaystyle \int \left(\dfrac{2}{x^4}+\dfrac{3}{x}+\dfrac{5}{\sqrt{x}} \right) \: dx\) \(-\dfrac{2}{3x^3}+3\ln|x|+10\sqrt{x}+c\) \(-\dfrac{2}{3x^3}+4 \ln|x|+20\sqrt{x}+c\) \(-\dfrac{5}{3x^3}+4\ln|x|+20\sqrt{x}+c\) \(-\dfrac{2}{3x^3}+2\ln|x|+5\sqrt{x}+c\) 🔍 Solution \begin{equation*} \begin{split} & \int...
QUESTION 04 \(\displaystyle \int x\sqrt{x\sqrt{x}}\:dx\) \(\dfrac{1}{11} \sqrt{\sqrt{x}}+c\) \(\dfrac{2}{11} x\sqrt{x\sqrt{x}}+c\) \(\dfrac{3}{11} x^2\sqrt{x\sqrt{x}}+c\) \(\dfrac{4}{11} x^2\sqrt{x\sqrt{x}}+c\) 🔍 Solution \begin{equation*} \begin{split} & \int...
QUESTION 04 \(\displaystyle \int x\sqrt{x\sqrt{x}}\:dx\) \(\dfrac{1}{11} \sqrt{\sqrt{x}}+c\) \(\dfrac{2}{11} x\sqrt{x\sqrt{x}}+c\) \(\dfrac{3}{11} x^2\sqrt{x\sqrt{x}}+c\) \(\dfrac{4}{11} x^2\sqrt{x\sqrt{x}}+c\) 🔍 Solution \begin{equation*} \begin{split} & \int...
QUESTION 05 \(\displaystyle \int \sqrt{x-2+\dfrac{1}{x}}\:dx\) \(\dfrac{1}{3}x\sqrt{x}-2\sqrt{x}+c\) \(\dfrac{2}{3}x\sqrt{x}-2\sqrt{x}+c\) \(\dfrac{2}{3}x^2 \sqrt{x}-2\sqrt{x}+c\) \(\dfrac{4}{3}x^2 \sqrt{x}-2\sqrt{x}+c\) 🔍 Solution \begin{equation*} \begin{split} & \int \sqrt{x-2+\frac{1}{x}}\:dx \\\\...
QUESTION 05 \(\displaystyle \int \sqrt{x-2+\dfrac{1}{x}}\:dx\) \(\dfrac{1}{3}x\sqrt{x}-2\sqrt{x}+c\) \(\dfrac{2}{3}x\sqrt{x}-2\sqrt{x}+c\) \(\dfrac{2}{3}x^2 \sqrt{x}-2\sqrt{x}+c\) \(\dfrac{4}{3}x^2 \sqrt{x}-2\sqrt{x}+c\) 🔍 Solution \begin{equation*} \begin{split} & \int \sqrt{x-2+\frac{1}{x}}\:dx \\\\...
QUESTION 06 \(\displaystyle \int_1^2 x^3 - 4x + 2 \: dx = \bbox{(\: \dotso \:...
QUESTION 08 Diketahui \(\displaystyle \int_1^{m + 1} (6x - 4) \: dx = 6 - m\) dimana \(m_1 >...